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16x^2+25x-82=0
a = 16; b = 25; c = -82;
Δ = b2-4ac
Δ = 252-4·16·(-82)
Δ = 5873
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-\sqrt{5873}}{2*16}=\frac{-25-\sqrt{5873}}{32} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+\sqrt{5873}}{2*16}=\frac{-25+\sqrt{5873}}{32} $
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